Molar Mass of NH₄NO₃

Ammonium nitrate. Contains two nitrogens in different oxidation states: −3 in NH₄⁺ and +5 in NO₃⁻.

Molar mass of NH4NO3
80.043 g/mol
2 × 14.007 + 4 × 1.008 + 3 × 15.999 = 80.043

Calculation, element by element

ElementAtomsAtomic mass (g/mol)SubtotalMass %
Nitrogen (N)214.00728.01435.00%
Hydrogen (H)41.0084.0325.04%
Oxygen (O)315.99947.99759.96%
Total80.043100%

= 0.12493 mol = 7.5236 × 1022 formula units

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NH₄NO₃ molar mass FAQ

What is the molar mass of ammonium nitrate (NH₄NO₃)?

80.043 g/mol. It is the sum of the atomic masses of every atom in the formula: 2 × 14.007 + 4 × 1.008 + 3 × 15.999 = 80.043 g/mol.

How many grams are in one mole of NH₄NO₃?

80.043 g. Molar mass is the mass of one mole (6.022 × 10²³ formula units), so 1 mol of NH₄NO₃ weighs 80.043 g and 0.5 mol weighs 40.022 g.

How many moles are in 10 g of NH₄NO₃?

10 g ÷ 80.043 g/mol = 0.1249 mol.

What is the percent composition of NH₄NO₃?

Nitrogen 35.00%, Hydrogen 5.04%, Oxygen 59.96%.

Is molecular weight the same as molar mass for NH₄NO₃?

Numerically yes: the molecular (or formula) weight is 80.043 u per formula unit, and the molar mass is 80.043 g/mol.

Molar masses of other common compounds