Molar Mass of NaNO₃

Sodium nitrate. A soluble salt of Na⁺ and the nitrate ion, NO₃⁻.

Molar mass of NaNO3
84.994 g/mol
1 × 22.99 + 1 × 14.007 + 3 × 15.999 = 84.994

Calculation, element by element

ElementAtomsAtomic mass (g/mol)SubtotalMass %
Sodium (Na)122.9922.99027.05%
Nitrogen (N)114.00714.00716.48%
Oxygen (O)315.99947.99756.47%
Total84.994100%

= 0.11766 mol = 7.0854 × 1022 formula units

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NaNO₃ molar mass FAQ

What is the molar mass of sodium nitrate (NaNO₃)?

84.994 g/mol. It is the sum of the atomic masses of every atom in the formula: 1 × 22.99 + 1 × 14.007 + 3 × 15.999 = 84.994 g/mol.

How many grams are in one mole of NaNO₃?

84.994 g. Molar mass is the mass of one mole (6.022 × 10²³ formula units), so 1 mol of NaNO₃ weighs 84.994 g and 0.5 mol weighs 42.497 g.

How many moles are in 10 g of NaNO₃?

10 g ÷ 84.994 g/mol = 0.1177 mol.

What is the percent composition of NaNO₃?

Sodium 27.05%, Nitrogen 16.48%, Oxygen 56.47%.

Is molecular weight the same as molar mass for NaNO₃?

Numerically yes: the molecular (or formula) weight is 84.994 u per formula unit, and the molar mass is 84.994 g/mol.

Molar masses of other common compounds