Molar Mass of CH₃COOH

Acetic acid (ethanoic acid, C₂H₄O₂). The acid in vinegar. Its Ka is about 1.8 × 10⁻⁵, which makes it a weak acid.

Molar mass of CH3COOH
60.052 g/mol
2 × 12.011 + 4 × 1.008 + 2 × 15.999 = 60.052

Calculation, element by element

ElementAtomsAtomic mass (g/mol)SubtotalMass %
Carbon (C)212.01124.02240.00%
Hydrogen (H)41.0084.0326.71%
Oxygen (O)215.99931.99853.28%
Total60.052100%

= 0.16652 mol = 1.0028 × 1023 formula units

Open CH₃COOH in the full molar mass calculator →

CH₃COOH molar mass FAQ

What is the molar mass of acetic acid (CH₃COOH)?

60.052 g/mol. It is the sum of the atomic masses of every atom in the formula: 2 × 12.011 + 4 × 1.008 + 2 × 15.999 = 60.052 g/mol.

How many grams are in one mole of CH₃COOH?

60.052 g. Molar mass is the mass of one mole (6.022 × 10²³ formula units), so 1 mol of CH₃COOH weighs 60.052 g and 0.5 mol weighs 30.026 g.

How many moles are in 10 g of CH₃COOH?

10 g ÷ 60.052 g/mol = 0.1665 mol.

What is the percent composition of CH₃COOH?

Carbon 40.00%, Hydrogen 6.71%, Oxygen 53.28%.

Is molecular weight the same as molar mass for CH₃COOH?

Numerically yes: the molecular (or formula) weight is 60.052 u per formula unit, and the molar mass is 60.052 g/mol.

Molar masses of other common compounds