Molar Mass of Fe₂O₃

Iron(III) oxide (rust, hematite). Iron is +3 here: two Fe³⁺ ions balance three O²⁻ ions.

Molar mass of Fe2O3
159.687 g/mol
2 × 55.845 + 3 × 15.999 = 159.687

Calculation, element by element

ElementAtomsAtomic mass (g/mol)SubtotalMass %
Iron (Fe)255.845111.69069.94%
Oxygen (O)315.99947.99730.06%
Total159.687100%

= 0.062623 mol = 3.7712 × 1022 formula units

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Fe₂O₃ molar mass FAQ

What is the molar mass of iron(iii) oxide (Fe₂O₃)?

159.687 g/mol. It is the sum of the atomic masses of every atom in the formula: 2 × 55.845 + 3 × 15.999 = 159.687 g/mol.

How many grams are in one mole of Fe₂O₃?

159.687 g. Molar mass is the mass of one mole (6.022 × 10²³ formula units), so 1 mol of Fe₂O₃ weighs 159.687 g and 0.5 mol weighs 79.844 g.

How many moles are in 10 g of Fe₂O₃?

10 g ÷ 159.687 g/mol = 0.06262 mol.

What is the percent composition of Fe₂O₃?

Iron 69.94%, Oxygen 30.06%.

Is molecular weight the same as molar mass for Fe₂O₃?

Numerically yes: the molecular (or formula) weight is 159.687 u per formula unit, and the molar mass is 159.687 g/mol.

Molar masses of other common compounds