Molar Mass of CuSO₄·₅H₂O

Copper(II) sulfate pentahydrate (blue vitriol). The five waters of crystallisation add 5 × 18.015 g/mol to the anhydrous salt.

Molar mass of CuSO4·5H2O
249.682 g/mol
1 × 63.546 + 1 × 32.065 + 9 × 15.999 + 10 × 1.008 = 249.682

Calculation, element by element

ElementAtomsAtomic mass (g/mol)SubtotalMass %
Copper (Cu)163.54663.54625.45%
Sulfur (S)132.06532.06512.84%
Oxygen (O)915.999143.99157.67%
Hydrogen (H)101.00810.0804.04%
Total249.682100%

= 0.040051 mol = 2.4119 × 1022 formula units

Open CuSO₄·₅H₂O in the full molar mass calculator →

CuSO₄·₅H₂O molar mass FAQ

What is the molar mass of copper(ii) sulfate pentahydrate (CuSO₄·₅H₂O)?

249.682 g/mol. It is the sum of the atomic masses of every atom in the formula: 1 × 63.546 + 1 × 32.065 + 9 × 15.999 + 10 × 1.008 = 249.682 g/mol.

How many grams are in one mole of CuSO₄·₅H₂O?

249.682 g. Molar mass is the mass of one mole (6.022 × 10²³ formula units), so 1 mol of CuSO₄·₅H₂O weighs 249.682 g and 0.5 mol weighs 124.841 g.

How many moles are in 10 g of CuSO₄·₅H₂O?

10 g ÷ 249.682 g/mol = 0.04005 mol.

What is the percent composition of CuSO₄·₅H₂O?

Copper 25.45%, Sulfur 12.84%, Oxygen 57.67%, Hydrogen 4.04%.

Is molecular weight the same as molar mass for CuSO₄·₅H₂O?

Numerically yes: the molecular (or formula) weight is 249.682 u per formula unit, and the molar mass is 249.682 g/mol.

Molar masses of other common compounds