Molar Mass of BaSO₄

Barium sulfate. An insoluble white solid, used in gravimetric analysis and as an X-ray contrast agent.

Molar mass of BaSO4
233.388 g/mol
1 × 137.327 + 1 × 32.065 + 4 × 15.999 = 233.388

Calculation, element by element

ElementAtomsAtomic mass (g/mol)SubtotalMass %
Barium (Ba)1137.327137.32758.84%
Sulfur (S)132.06532.06513.74%
Oxygen (O)415.99963.99627.42%
Total233.388100%

= 0.042847 mol = 2.5803 × 1022 formula units

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BaSO₄ molar mass FAQ

What is the molar mass of barium sulfate (BaSO₄)?

233.388 g/mol. It is the sum of the atomic masses of every atom in the formula: 1 × 137.327 + 1 × 32.065 + 4 × 15.999 = 233.388 g/mol.

How many grams are in one mole of BaSO₄?

233.388 g. Molar mass is the mass of one mole (6.022 × 10²³ formula units), so 1 mol of BaSO₄ weighs 233.388 g and 0.5 mol weighs 116.694 g.

How many moles are in 10 g of BaSO₄?

10 g ÷ 233.388 g/mol = 0.04285 mol.

What is the percent composition of BaSO₄?

Barium 58.84%, Sulfur 13.74%, Oxygen 27.42%.

Is molecular weight the same as molar mass for BaSO₄?

Numerically yes: the molecular (or formula) weight is 233.388 u per formula unit, and the molar mass is 233.388 g/mol.

Molar masses of other common compounds