Molar Mass of KMnO₄

Potassium permanganate. A strong oxidising agent with manganese in the +7 oxidation state, used in redox titrations.

Molar mass of KMnO4
158.032 g/mol
1 × 39.098 + 1 × 54.938 + 4 × 15.999 = 158.032

Calculation, element by element

ElementAtomsAtomic mass (g/mol)SubtotalMass %
Potassium (K)139.09839.09824.74%
Manganese (Mn)154.93854.93834.76%
Oxygen (O)415.99963.99640.50%
Total158.032100%

= 0.063278 mol = 3.8107 × 1022 formula units

Open KMnO₄ in the full molar mass calculator →

KMnO₄ molar mass FAQ

What is the molar mass of potassium permanganate (KMnO₄)?

158.032 g/mol. It is the sum of the atomic masses of every atom in the formula: 1 × 39.098 + 1 × 54.938 + 4 × 15.999 = 158.032 g/mol.

How many grams are in one mole of KMnO₄?

158.032 g. Molar mass is the mass of one mole (6.022 × 10²³ formula units), so 1 mol of KMnO₄ weighs 158.032 g and 0.5 mol weighs 79.016 g.

How many moles are in 10 g of KMnO₄?

10 g ÷ 158.032 g/mol = 0.06328 mol.

What is the percent composition of KMnO₄?

Potassium 24.74%, Manganese 34.76%, Oxygen 40.50%.

Is molecular weight the same as molar mass for KMnO₄?

Numerically yes: the molecular (or formula) weight is 158.032 u per formula unit, and the molar mass is 158.032 g/mol.

Molar masses of other common compounds