Vanadium Electron Configuration
Orbital diagram
- Valence electrons
- 5
- Unpaired electrons
- 3
- Block
- d-block
- Magnetism (atom)
- paramagnetic
Electrons per shell
| K (n = 1) | 2 |
|---|---|
| L (n = 2) | 8 |
| M (n = 3) | 11 |
| N (n = 4) | 2 |
Vanadium ion configurations
| Ion | Electrons | Configuration |
|---|---|---|
| V5+ | 18 | [Ne] 3s2 3p6 |
| V3+ | 20 | [Ar] 3d2 |
How to write it
Place 23 electrons into subshells in the Aufbau order (1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p), filling s with 2, p with 6, d with 10 and f with 14. Vanadium sits in period 4, group 5, in the d-block, so its last electron enters a d subshell. Replacing the inner electrons with the previous noble gas gives the shorthand [Ar] 3d3 4s2.
Try vanadium and its ions in the calculator, or see the full vanadium data sheet.
Vanadium electron configuration FAQ
What is the electron configuration of vanadium?
1s² 2s² 2p⁶ 3s² 3p⁶ 3d³ 4s². Shorthand (noble gas) notation: [Ar] 3d³ 4s².
What is the noble gas configuration of vanadium?
[Ar] 3d³ 4s². The bracket stands for the Ar core electrons.
How many valence electrons does vanadium have?
5 (2 outer s + 3 d electrons; 2 in the outermost shell).
How many unpaired electrons does vanadium have?
3 in the ground state, following Hund’s rule. An atom with unpaired electrons is paramagnetic.
What is the electron configuration of V5+?
[Ne] 3s² 3p⁶ (18 electrons). Transition metal cations lose their outer s electrons before d electrons.
What is the electron configuration of V3+?
[Ar] 3d² (20 electrons). Transition metal cations lose their outer s electrons before d electrons.