Iodine Electron Configuration
Orbital diagram
- Valence electrons
- 7
- Unpaired electrons
- 1
- Block
- p-block
- Magnetism (atom)
- paramagnetic
Electrons per shell
| K (n = 1) | 2 |
|---|---|
| L (n = 2) | 8 |
| M (n = 3) | 18 |
| N (n = 4) | 18 |
| O (n = 5) | 7 |
Iodine ion configurations
| Ion | Electrons | Configuration |
|---|---|---|
| I− | 54 | [Kr] 4d10 5s2 5p6 |
How to write it
Place 53 electrons into subshells in the Aufbau order (1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p), filling s with 2, p with 6, d with 10 and f with 14. Iodine sits in period 5, group 17, in the p-block, so its last electron enters a p subshell. Replacing the inner electrons with the previous noble gas gives the shorthand [Kr] 4d10 5s2 5p5.
Try iodine and its ions in the calculator, or see the full iodine data sheet.
Iodine electron configuration FAQ
What is the electron configuration of iodine?
1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁵. Shorthand (noble gas) notation: [Kr] 4d¹⁰ 5s² 5p⁵.
What is the noble gas configuration of iodine?
[Kr] 4d¹⁰ 5s² 5p⁵. The bracket stands for the Kr core electrons.
How many valence electrons does iodine have?
7 (outer shell (n = 5)).
How many unpaired electrons does iodine have?
1 in the ground state, following Hund’s rule. An atom with unpaired electrons is paramagnetic.
What is the electron configuration of I−?
[Kr] 4d¹⁰ 5s² 5p⁶ (54 electrons).